Question

What is the energy carried by a quantum of yellow light if its frequency is 6x10^14Hz?

Answer 1

Explanation:

energy of 1 quantum= energy of 1 photon= h*Freq.

h=(6.62/10³⁴)m²kg/s

Freq.= 6*10¹⁴ hz

therefore energy= 6.62*6*10¹⁴/10³⁴ joules

=39.72 * 10^(-20) joules

Answer 2

Answer:

The energy carried by a quantum of yellow light is 3.96×10⁻¹⁹J.

Explanation:

The energy carried by a quantum of yellow light is given as,

$E=h\nu$         (1)

Where,

E=energy carried by a quantum of yellow light

h=planck's constant=6.6×10⁻³⁴Joule-Second

ν=frequency of yellow light

From the question we have,

Frequency of yellow light(ν)=6×10¹⁴Hz

By substituting the value of Planck's constant and frequency of yellow light in equation (1) we get;

$E=6.6\times 10^-^3^4\times 6\times 10^1^4$

$E=39.6\times 10^-^2^0$

$E=3.96\times 10^-^1^9J$

Hence,  the energy carried by a quantum of yellow light is 3.96×10⁻¹⁹J.