what is the energy for 1mole of photons of radiation whose frequency is 5×10^14Hz
Answers
Answered by
2
here's the solution.
Attachments:
Answered by
1
Energy of one photon is given by the expression E = hV
Where, h = PlancKs constant = 6.636 x 10-34 J s-1
V= Frequency of radiation = 5x 1014 Hz= 5 x 1014 s-1.
E= (6.636 x 1034 J s-1 x 5 x 1014 s-1)= 33.18 x 1020J
One mole of photon = 6.023 x 1023 photons
Therefore,
Energy of one mole of photon = (6.023 x 1023 x 33.18 x 10-20 J) = 199.84 x 103 J
Energy of one mole of photon = 199.84 kJ
Where, h = PlancKs constant = 6.636 x 10-34 J s-1
V= Frequency of radiation = 5x 1014 Hz= 5 x 1014 s-1.
E= (6.636 x 1034 J s-1 x 5 x 1014 s-1)= 33.18 x 1020J
One mole of photon = 6.023 x 1023 photons
Therefore,
Energy of one mole of photon = (6.023 x 1023 x 33.18 x 10-20 J) = 199.84 x 103 J
Energy of one mole of photon = 199.84 kJ
Similar questions