Physics, asked by dwalk07, 1 year ago

What is the energy in eV of the electron of a hydrogen atom for the orbit designated n = 4?

Answers

Answered by rjeeeacademy

1

E = -13.6eV/n^2
= -13.6eV/4^2
= -0.85eV

dwalk07: Thank you!!

rjeeeacademy: Welcome

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