Question

What is the energy (kj/mol) associated with the de excitation of an electron from n=6 to n=2 in he+ ion?

Answer 1

1/ ​ λ = R [ 1/n12 - 1/n22 ]

1/ λ = 1.097 * 107 [ 1/36 - 1/ 4 ]

1/ λ = 1.097 * 107( -8 / 36)

1/ λ = 0.219 *107

λ = 4.566 * 10-7

E = hc/ λ

6.6 * 10-34 . 3*108

4.566 * 10-7

1.96 / 4.56 * 10 -19 eV

0.429 *10 -19 eV