What is the energy of a photon of red light that has a frequency of 4.48x105 GHz?
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Answer:
The energy of a photon with frequency 4.48×10⁵ GHz is 2.97×10⁻¹⁹ Joules.
Explanation:
Given,
frequency of light = 4.48×10⁵ GHz
⇒ = 4.48×10⁵×10⁹Hz = 4.48×10¹⁴Hz
The energy associated with a photon is given by,
E = hν
where,
h = Planck's constant= 6.626×10⁻³⁴Js
ν = frequency of the radiation
substituting values of h and ν,
E = 6.626×10⁻³⁴ × 4.48×10¹⁴
⇒ = 2.97×10⁻¹⁹ J
Hence, the energy of a photon is 2.97×10⁻¹⁹ Joules.
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