What is the energy of photon having wavelength 6000a?
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Energy = 1240/wavelength in nm
E = 1240/6000 angstrom
= 1240/6000*10^-1 nm
=1240*10^-2/6 nm
= 206.66 * 10^-2 = 2.07x10^-2 j.
E = 1240/6000 angstrom
= 1240/6000*10^-1 nm
=1240*10^-2/6 nm
= 206.66 * 10^-2 = 2.07x10^-2 j.
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