Question

What is the energy of the 3^rd line in the bracket series for hydrogen atom?

Answer 1

Answer:

1/λ = R(1/4² - 1/7²)

⇒ 1/λ = R(1/16 - 1/49)

⇒ 1/λ = R(0.04209)

⇒ 1/λ = R × 10.04209

λ = 911/10.04209

λ = 21643.15 Angstrom

Explanation:

I THINK SO THIS IS THE ANSWER