Question

What is the energy released in joules during transition from n=5 to n=2?

Answer 1

Answer:

(2.86 z^2) eV

if z=1, energy released = 2.86 eV

Explanation:

∆E = - 13.6 z^2 (1/n2^2 - 1/n1^2) eV

where, z = atomic no of hydrogen like atom

n1 - initial energy state

n2 - final energy state

so,

∆E = - 13.6 z^2 ( 1/2^2 - 1/5^2)

= - 13.6 z^2 ( 1/4 - 1/25)

= - 13.6 z^2 ( 21/100)

= - 2.86 z^2 eV