Question

What is the energy released (magnitude) in Joules during transition of electron from 5nd energy level to 2nd energy level in a hydrogen atom?

Answer 1

I hope this is the answer you want

Answer 2

Answer:

Energy released (magnitude)=(3803.97474)($10^{-36}$)  Joule.

Explanation:

In order to calculate energy released due to the transition of electron.

we have,

E=hμ=$\frac{hc}{lamba}$=($\frac{hc}{R}$)($\frac{1}{n_{2} ^{2} }$-$\frac{1}{n_{1} ^{2} }$).

where R is the rydberg's constant($\frac{1}{R}$=911.267angstroms ).

$n_{1}$ and $n_{2}$ are the lower and upper energy level respectively.

h is plank's constant and c is the speed of light in vacuum.

h=(6.626)($10^{-34}$) J.s.

c=(3)($10^{8}$) m/s.

putting the values; we get

∴E=(6.626)(3)(911.267)($10^{-10}$)()($10^{-34}$)($10^{8}$)($\frac{1}{4}$-$\frac{1}{25}$)

E=(3803.97474)($10^{-36}$)  Joule.