Question

What is the energy required to launch a m kg satellite from earth's surface in a circular orbit at an altitude of 7R ? (R = radius of the earth)

Answer 1

Answer:

As we know, Gravitational potential energy = - GM /r

and orbital velocity, v0 = vGM/R+h

Ef = ½ mv20 – GMm/3R = ½ m GM/3R – GMm/3R

= GMm/3R (1/2-1) = - GMm/6R

Ei = - GM/R + K

Ei = Ef

Therefore minimum required energy, K = 5GMm/6R

Answer 2

Answer:

k= 5gmr

= 6

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