What is the energy stored in the magnetic field at a solenoid of 40 cm long and 4 cm diameter wound with 100 turns of wire carrying a current at 20a?
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L = N^2 × u × A ÷ l
10000 × 4 × 10 ^-7 × 3.14 × 3.14 × 4 / 40
= 0.0039
E = L× I^2 / 2
= 0.0039 × 20 /2
=0 039
10000 × 4 × 10 ^-7 × 3.14 × 3.14 × 4 / 40
= 0.0039
E = L× I^2 / 2
= 0.0039 × 20 /2
=0 039
Answered by
0
Answer:. 0.789 joule
Explanation:
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