Question

What is the enthalpy change, ΔH in kJ, for the following reaction?
2Mg(s) + SiCl4(l)→ Si(s) + 2MgCl2(s)
Use the following:
Si(s) + 2Cl2(g) → SiCl4(l) ΔH = –687 kJ
Mg(s) + Cl2(g) → MgCl2(s) ΔH = –641 kJ

Answer 1

Answer:

2*(-641)+-(-687)

Explanation:

2 of eqn 2nd and reverse of eqn 1