Question

What is the entropy change of an engine that operates at 1000C
when 231.5 k.cal of heat is supplied to it?

Answer 1

Answer:

The change in entropy would be given as ΔS=ΔS

1

+ΔS

2

ΔS

1

is to melt the ice and ΔS

2

is to rise the temperature. Thus we get ΔS=

T

mL

+m∫

T

1

T

2

T

dT

ΔS=

273

1×80

+1×ln

273

313

=0.28+0.13=0.41 cal/

o

C