Question

What is the equation, in point-slope form, of the line that is parallel to the given line and passes through the point ()?

Answer 1

As according to point slope from the formula for line equation of a line

=>  y-y1 = m (x-x1)

=> As it is given that the line passes through origin the equation can also be

= y = mx

From equation 1 and 2,

mx - mx1 + y1 = mx

=> y1 = mx1

Not sure about the answer.

I can tell the answer if you can provide the point.