Question

What is the equation in slope-intercept form of the line that passes through the points (-4,2) and (12,6)?

Answer 1

Answer:

hope it helps

Step-by-step explanation:

Recall that the slope of a line m = (y2 - y1) / (x2 - x1). We are given the coordinates of two points, both of which lie on the line (the line passes through them): (-4,2) and 12,6). y = 1/4 * x + 3.

Answer 2

Given:

The points through which the line passes: (-4, 2), (12, 6).

To find:

Equation of the line in the slope-intercept form.

Solution:

We can represent the slope of a line by

$m=\frac{y_2-y_1}{x_2-x_1}$

Putting the values,

⇒$m=\frac{6-2}{12-(-4)}$

⇒$m=\frac{4}{16}$

⇒$m=\frac{1}{4}$

Now, the slope-intercept form of a line is

$y=mx+c$

We can find the value of $c$ by putting the value of any one of the points,

$2=\frac{1}{4}$×$(-4)+c$

⇒$c=2+1$

⇒$c=3$

So the slope of the line that passes through the points (-4, 2) and (12, 6) is

$y=\frac{1}{4} x+3$

Hence, the required equation of the line is $y=\frac{1}{4} x+3$.