Question

What is the equation in slope-intercept form of the line that crosses the x-axis at 36
and is perpendicular to the line represented by y = -4/9x + 5?

Answer 1

Given :  line that crosses the x-axis at 36 and is perpendicular to the line represented by y = -4/9x + 5

To Find : equation in slope-intercept form

Solution:

slope-intercept form  :  y=mx+b  

intercept form x/a  + y/b  = 1

normal  form   ax + by + c = 0

y = -4/9x + 5

=> Slope = - 4/9

Hence Slope of perpendicular line  = 9/4

intersect x axis at  36

=> passes through point ( 36 , 0)

=> y  - 0  = (9/4)(x - 36)

=> y =  (9/4)x-  81

y =   (9/4)x-  81

is the required equation

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