Math, asked by ir355936, 2 months ago

what is the equation in the slope intercept form of the line that passes through the points (-4,2)and (12,6)

Answers

Answered by Anonymous
40

Given Point

A(-4,2) and B(12,6)

To Find Equation in the slope Intercept form

Formula

(y-y₁) = m(x-x₁)

Formula to find Slope(m)

m = (y₂ - y₁)/(x₂ - x₁)

We have

x₁ = -4 , y₁ = 2 , x₂ = 12 and y₂ = 6

Now Find Slope

m = (6 - 2)/(12 + 4)

m = 4/16

m = 1/4

Now Put the value on

(y - y₁) = m(x - x₁)

(y - 2) = 1/4(x + 4)

4(y - 2) = 1(x + 4)

4y - 8 = x + 4

x - 4y + 4 + 8 = 0

x - 4y + 12 = 0

Answer

Equation → x - 4y + 12 = 0

Answered by Anonymous
72

Answer:

Given :-

  • The slope intercept form of the line passes through the points of (- 4 , 2) and (12 , 6).

To Find :-

  • What is the equation in the slope intercept.

Formula Used :-

\clubsuit Slope Formula :

\longmapsto \sf\boxed{\bold{\pink{m =\: \dfrac{y_2 - y_1}{x_2 - x_1}}}}\\

where,

  • m = Slope
  • (x₁ , y₁) = Co-ordinates of first point in the line
  • (x₂ , y₂) = Co-ordinates of second point in the line

\clubsuit Point-Slope Formula :

 \longmapsto \sf\boxed{\bold{\pink{y - y_1 =\: m(x - x_1)}}}\\

where,

  • m = Slope
  • (x , y) = Variables
  • (y₁ , x₁) = Co-ordinates of a points on a line

Solution :-

First, we have to find the value of m :

Given points :

\mapsto (- 4 , 2)

\mapsto (12 , 6)

Then,

  • x₁ = - 4
  • x₂ = 12
  • y₁ = 2
  • y₂ = 6

According to the question by using the formula we get,

 \implies \sf m =\: \dfrac{6 - 2}{12 - (- 4)}

 \implies \sf m =\: \dfrac{4}{12 + 4}

 \implies \sf m =\: \dfrac{\cancel{4}}{\cancel{16}}

 \implies \sf\bold{\green{m =\: \dfrac{1}{4}}}

Now, we have to find the equation in the slope intercept :

Given :

  • x₁ = - 4
  • y₁ = 2
  • m = ¼

According to the question by using the formula we get,

 \implies \sf (y - 2) =\: \dfrac{1}{4}(x - \{- 4\})

 \implies \sf (y - 2) =\: \dfrac{1}{4}(x + 4)

By doing cross multiplication we get,

 \implies \sf 4(y - 2) =\: 1(x + 4)

\implies \sf 4y - 8 =\: x + 4

 \implies \sf x + 4 - 4y + 8 =\: 0

 \implies \sf x - 4y + 4 + 8 =\: 0

 \implies \sf\bold{\red{x - 4y + 12 =\: 0}}

\therefore The equation in the slope intercept is x - 4y + 12 = 0.

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