what is the equation in the slope intercept form of the line that passes through the points (-4,2)and (12,6)
Answers
Given Point
A(-4,2) and B(12,6)
To Find Equation in the slope Intercept form
Formula
(y-y₁) = m(x-x₁)
Formula to find Slope(m)
m = (y₂ - y₁)/(x₂ - x₁)
We have
x₁ = -4 , y₁ = 2 , x₂ = 12 and y₂ = 6
Now Find Slope
m = (6 - 2)/(12 + 4)
m = 4/16
m = 1/4
Now Put the value on
(y - y₁) = m(x - x₁)
(y - 2) = 1/4(x + 4)
4(y - 2) = 1(x + 4)
4y - 8 = x + 4
x - 4y + 4 + 8 = 0
x - 4y + 12 = 0
Answer
Equation → x - 4y + 12 = 0
Answer:
Given :-
- The slope intercept form of the line passes through the points of (- 4 , 2) and (12 , 6).
To Find :-
- What is the equation in the slope intercept.
Formula Used :-
Slope Formula :
where,
- m = Slope
- (x₁ , y₁) = Co-ordinates of first point in the line
- (x₂ , y₂) = Co-ordinates of second point in the line
Point-Slope Formula :
where,
- m = Slope
- (x , y) = Variables
- (y₁ , x₁) = Co-ordinates of a points on a line
Solution :-
➤ First, we have to find the value of m :
Given points :
(- 4 , 2)
(12 , 6)
Then,
- x₁ = - 4
- x₂ = 12
- y₁ = 2
- y₂ = 6
According to the question by using the formula we get,
➤ Now, we have to find the equation in the slope intercept :
Given :
- x₁ = - 4
- y₁ = 2
- m = ¼
According to the question by using the formula we get,
By doing cross multiplication we get,
The equation in the slope intercept is x - 4y + 12 = 0.