Question

What is the equation of a circle whose center is at (2, -4) and is tangent to the line x= -2?

A. (x-2)^2 + (y+4)^2 = 4
B. (x+2)^2 + (y-4)^2 = 16
C. (x+2)^2 + (y-4)^2 = 4
D. (x-2)^2 + (y+4)^2 = 16

Answer 1

Step-by-step explanation:

C) is answer for this question

Answer 2

We know that the general equation for a circle is $(x-h)^{2}+(y-k)^{2}=r^{2}$, where ( h, k ) is the center and r is the radius.

Given that center is (2,-4) and the tangent is -2.

Therefore x=-2 and y=4

From the problem, we get the circle equation as,

$(x-2)^{2}+(y+4)^{2} =16$

That is the correct answer is option D.