Question

What is the equation of a circle with center (1,-3) and radius 6?

Answer 1

Answer: Please find the attached file.

Step-by-step explanation:

Answer 2

The equation of the circle is $(x-1)^2+(y+3)^2=36$.

Step-by-step explanation:

The standard form of a circle is

$(x-h)^2+(y-k)^2=r^2$

where, (h,k) is center and r is radius of the circle.

It is given that center of the circle is (1,-3) and radius is 6.

Substitute h=1, k=-3 and r=6 in the above equation.

$(x-1)^2+(y-(-3))^2=(6)^2$

$(x-1)^2+(y+3)^2=36$

Therefore, the equation of the circle is $(x-1)^2+(y+3)^2=36$.

#Learn more

Find the equation of a circle of radius 6 units and whose center lies on the negative direction of x-axis at a distance of 4 units from the origin .

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