Question

What is the equation of a circle with center (-3, -1) that contains the point (1, 2)?


A,(x + 3)2 + (y + 1)2 = 25


B.(x − 3)2 + (y − 1)2 = 36


C.(x + 3)2 + (y − 1)2 = 36


D.(x − 1)2 + (y − 2)2 = 25

Answer 1

Answer:

option 3 : (x+3)²+ (y+1)²= 25

Step-by-step explanation:

Equation of a circle with centre (c1,c2) and a point (a,b) is

(x-c1)² + (x-c2)² = r²

Finding out the radius with the help of distance in Co ordinates will give the radius as 5

(x+3)² +(y+1)²= 5² = 25