Question

What is the equation of a line, in general form, that passes through point (1, -2) and has a slope of 1/3

Answer 1

Answer:

$= >$

Given,

slope of line = 1/3

line passes through point =(1,-2)

let,

point (1,-2)=(x1,y1)

Explanation =

by slope point form

(y-y1)= m(x-x1)

(y-(-2))=1/3(x-1)

3(y+2)=x-1

3y+6+1-x=0

3y-x+7=0

x-3y-7=0

therefor the eqn of the line

is x-3y-7=0

Answer 2

Answer 3x-y-7=0:

Step-by-step explanation: