What is the equation of a line, in point-slope form, that passes through (−2, −6) and has a slope of 13 ?
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the equation of line , in point- slope form
y - y1 = m (x - x1)
here
x1 = - 2
y1 = - 6
m = 13
y - (-6) = 13(x - (-2) )
y +6 = 13 (x + 2 )
y + 6 = 13 x + 26
y = 13x + 26 - 6
y = 13x + 20
y - y1 = m (x - x1)
here
x1 = - 2
y1 = - 6
m = 13
y - (-6) = 13(x - (-2) )
y +6 = 13 (x + 2 )
y + 6 = 13 x + 26
y = 13x + 26 - 6
y = 13x + 20
angelann4201:
thankyou it helped
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