What is the equation of a line in slope-intercept form that crosses the x-axis at 36 and is perpendicular to the line represented by
y = -49x + 5 ?
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Given : line that crosses the x-axis at 36 and is perpendicular to the line represented by y = -4/9x + 5
To Find : equation in slope-intercept form
Solution:
slope-intercept form : y=mx+b
intercept form x/a + y/b = 1
normal form ax + by + c = 0
y = -4/9x + 5
=> Slope = - 4/9
Hence Slope of perpendicular line = 9/4
intersect x axis at 36
=> passes through point ( 36 , 0)
=> y - 0 = (9/4)(x - 36)
=> y = (9/4)x- 81
y = (9/4)x- 81
is the required equation
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