Question

What is the equation of a line parallel to y = 3x + 7 and through the point (8, 6)?

Answer 1

<marquee behaviour-move><font color="orange"><h1>Satyammm</h1></marquee>

8,6 this in in quadrant 4

follow mee

Answer 2

The equation of a line parallel to y = 3x + 7 and through the point (8, 6) is

y = 3x - 18

Step-by-step explanation:

Given:

The equation of line

$y=3x+7$

To find out:

Equation of line parallel to the given line and passing through $(8,6)$

Solution:

Comparing the line $y=3x+7$ with general equation of line in slope-intercept form $y=mx+c$

We get

Slope of the line

$m=3$

A line that is parallel to the given line will also have its slope as $3$

Therefore, equation of line having slope 3 and passing through point $(8,6)$

$(y-6)=3(x-8)$

$y-6=3x-24$

$\implies y=3x-18$

Hope this answer is helpful.

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