Question

What is the equation of a line passing through "P" and parallel to x - 3y + 4 = 0?​

Answer 1

Answer:

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Answer 2

GIVEN,

equation of line x-3y+4=0, point P.

TO FIND,

equation of the line passing through p parallel to X-3Y+4=0

SOLUTION,

Solving the given line equation to find the value of the slope.

⇒ X-3Y+4=0

⇒ 3Y=X+4

⇒ $Y=\frac{1}{3} X+\frac{4}{3}$

Hence slope of this line is a variable of X i.e $\frac{1}{3}$

now the required point is P

to find out the equation of the line we will use the point-slope form of the equation of a line,

that is,

(Y-Y₁) = m (X-X₁)

here 'm' is the slope of the like that we found, and (y₁,x₁) is the point P.