Question

What is the equation of a line that is perpendicular to −x+3y=9 and passes through the point (−3, 2)?

Answer 1

Answer:

$required \: equation \: x + 3y = 3$

Step-by-step explanation:

$let \: the \: required \: equation \: be \\ x + 3y = k \\ \\ put \: ( - 3 \: \: \: \: 2) \: in \: above \: equation \: \: \: then \\ \\ - 3 + 3(2) = k \\ \\ therefore \: \: \: k = 3 \\ \\ \\ required \: equation \: x + 3y = 3$