what is the equation of a parabola with the vertex (3,7) and the focus (5,7)?
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Answer:
( y - 7 )² = 4 (2) ( x - 3)²
Step-by-step explanation:
Given Vertex (3,7) and focus (5,7)
It can be easily noticed that focus and vertex lie on the same horizontal line y = 7
Obviously, the axis of symmetry is a horizontal line ( a line perpendicular to y-axis). Also, the focus lies to the right of the vertex so the parabola will open up rightward.
( y- k )² = 4a ( x-h)²
a = 5-3 = 2 as y coordinates are the same.
Since the focus lies to the left of vertex, a = 2
( y - 7 )² = 4 (2) ( x - 3)²
OR
y²+49-14y = 8 ( x²+9-6x )
y²-14y+49 = 8x²-48x+72
8x²-y²-49x-14y+23 =0
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