what is the equation of circle with centre at origin and radius 3
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Answer:
Step-by-step explanation:
The general equation of a circle is:
(x−h)^2+(y−k)^2=r^2
Center (h,k) centered at the origin.
Therefore (h,k)=(0,0)
Radius 3 so r^2=(3)^2=9
We can substitute into our equation to get:
(x−0)^2+(y−0)^2=9
x^2+y^2=9
#answerwithquality #BAL
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