Question

what is the equation of line through (2,-3)and(4,1)​

Answer 1

Answer:

i think this will help u

Answer 2

$\leadsto\tt (y-y1)=\frac{y2-y1}{x2-x1}(x-x1)$

$\leadsto\tt (y+3)=\frac{1+3}{4-2} (x-2)\\</p><p> \leadsto\tt (y+3)=\frac{4}{2}(x-2)\\ \leadsto\tt 2y+6=4x-8\\ \leadsto\tt 4x-2y-14=0\\ \leadsto\tt 2(2x-y-7)=0\\ \leadsto\tt 2x-y-7=0$

Hence,

$\tt The\: equation\:ofline\:is =2x-y-7=0$