Question

what is the equation of plane containing z axis and passing through the point (1,2,3)

Answer 1

Answer: x+y-3 = 0

Step-by-step explanation:

Given that : Plane containing z-axis, so the points will be (1,1,0) and passes through the point (1,2,3)

So, we have find the equation which is containing z-axis and passes through the point (1,2,3)

Here, x1 = 1, y1 = 2 and z1 = 3

Now, Equation : 1(x–x1)+1(y–y1)+0(z–z1) = 0

=> 1(x-1)+1(y-2)+0(z-3) = 0

=> (x-1)+(y-2) = 0

=> x+y-3 = 0

So, the equation will be x+y-3 = 0