Question

What is the equation of tangent line for

f(x) = xex at x = 1

Answer 1

Answer:

Given f(x) = xex(1 – x) f'(x) = ex(1 – x) + xex(1 – x) (1 – 2x) = ex(1 – x) (1 + x(1 – 2x)) = – ex(1 – x) (2x2 – x – 1) = – ex(1 – x) (2x2 – 2x + x – 1) = – ex(1 – x)(x – 1)(2x + 1) Read more on Sarthaks.com - https://www.sarthaks.com/540073/if-f-x-xe-x-1-x-then-f-x-is-a-increasing-on-1-2-1-b-decreasing-on-r