Question

What is the equation of the circle with center (-6,7) that passes through the point (4,-2)?

A. (x+6)^2 + (y-7)^2 = 181
B. (x-6)^2 + (y+7)^2 = 181
C. (x+6)^2 + (y-7)^2 = 9
D. (x-6)^2 + (y+7)^2 = 9

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

since the equation of circle is

(x-h)^2+(y-k)^2 = r^2

with center (h, k) = (-6,7) (given) .

(x+6)^2+(y-7)^2 = r^2 ......(I)

it passes through (4,-2)

then

(4+6)^2 + ( -2-7)^2 = r^2

10^2 + (-9)^2 = r^2

181 = r^2

putting value of r^2 in (I) we get

(x+6)^2+(y-7)^2 = 181 is right answer