Question

What is the equation of the line pass through (1,1) and perpendicular to the line 4x-2=7

Answer 1

Answer:

Slope of line 4x - 2y = 7 is 4/2 = 2

then slope of perpendicular to this line is -1/2.

Eq. or req. line is

$(y - 1) = - \frac{1}{2} (x - 1)$

$2y - 2 = - x + 1$

$x + 2y = 3$

Ans

Mark BRAINLIEST if this will helpful to you. Thanks