Math, asked by nbais9309, 1 year ago

What is the equation of the line passing through the point (-1,3) and having x-intercept of 4 units?

Answers

Answered by jatinrao1
2
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Answered by sk940178
4

The equation of the straight line is 3x + 5y = 12

Step-by-step explanation:

Let the equation of the straight line in intercept form be \frac{x}{a} + \frac{y}{b} = 1 ......... (1)

Where the x-intercept length is a and the y-intercept length b.

Given that a = 4 units.

Hence, the equation becomes \frac{x}{4} + \frac{y}{b} = 1 ......... (2)

If the straight line passes through the point (-1,3) then it must satisfy the equation (2).

Hence, \frac{- 1}{4} + \frac{3}{b} = 1

\frac{3}{b} = \frac{5}{4}

b = \frac{12}{5}

Therefore, the equation of the straight line becomes \frac{x}{4} + \frac{5y}{12}  = 1

⇒ 3x + 5y = 12 (Answer)

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