What is the equation of the line passing through the point (-2, 6) and whose slope is 3/5?
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A general equation for line having slope m is , y = mx + c , where m is slope of line .
Here m =
3
7
,
So, 3y=7x+3c or 3y=7x+C
Now to eliminate C we will use the information that line passes through (3,-5),
−15=7(3)+C which gives c=−36 .
So equation of line is , 7x−3y−36=0
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