Question

What is the equation of the line passing through the point (4, -7) with slope -5/2

Answer 1

Step-by-step explanation:

line passing through the point (x1, y1) with slope m is

y-y1=m(x-x 1)

so

y-(-7)= -5/2(x-4)

y+7= -5/2(x-4)

2(y+7)= -5(x-4)

2y+14= -5x+20

5x+2y+14-20=0

5x+2y-4=0