what is the equation of the line perpendicular to 2x-3y=13 that passes through the point (-6,5)
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Step-by-step explanation: Plzz mark me as brainiest plzzzzzzz
slope of given line is -a/b = 2/3
for perpendicular line m1*m2 = -1 hence slope of perpendicular line is -3/2
now y = m*x +c i.e. line equation
and put (-6,5) in this line
so answer is 3*x + 2*y = 14
hope it will help you
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