Question

what is the equation of the line perpendicular to 2x-3y=13 that passes through the point (-6,5)

Answer 1

here is your answer......

Answer 2

Answer:

Step-by-step explanation: Plzz mark me as brainiest plzzzzzzz

slope of given line is -a/b = 2/3

for perpendicular line m1*m2 = -1 hence slope of perpendicular line is -3/2

now y = m*x +c i.e. line equation

and put (-6,5) in this line

so answer is 3*x + 2*y = 14

hope it will help you