Question

What is the equation of the line perpendicular to the line 2x + 3y= -6 and having y-intercept 3?

Answer 1

Answer:

2y = 3x + 6

Step-by-step explanation:

Slope of line 2x + 3y = -6 is -2/3 (m')

Let slope of other line be m"

If two lines are parallel, then the product of their slopes is -1

m'm"= -1

-2/3 .m" = -1

m" = 3/2

One point on this line is given, i.e., (0,3)

So, by Slope intercept form

y-y' = m"(x-x')

y-3 = 3/2 . (x-0)

2y - 6 = 3x

2y = 3x + 6

HOPE IT WILL HELP YOU!!!

HOPE IT WILL HELP YOU!!!PLEASE DO NOT FORGET TO MARK THIS ANSWER AS BRAINLIEST

[For further questioning, you can follow me.]

Answer 2

Step-by-step explanation:

GLORY TO GOD JESUS. I M CHENNAI RACE STUDENT