Question

What is the equation of the line that is parallel to the line y − 1 = 4(x + 3) and passes through the point (4, 32)?

Answer 1

4x+12=y-1

4x-y=-11

slope of the above equation= 4

pt(4,32)

y-y1=m(x-x1)

y-32=4(x-4)

4x-16=y-32

4x-y=-16