What is the equation of the line that passes through (−2,1) and is perpendicular to 3y=x-4
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Step-by-step explanation:
Perpendicular lines have opposite-reciprocal slopes, so the slope of the line we want to find is 1/2. Plugging in the point given into the equation y = 1/2x + b and solving for b, we get b = 6. Thus, the equation of the line is y = ½x + 6. Rearranged, it is –x/2 + y = 6.
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Answer:
The product of slopes of perpendicular lines is -1. The slope of the given line is
m1 = 1/3
The slope of the perpendicular line is
m2 = -1/m1 = -1/(1/3) = -3
In point slope form, the equation of the perpendicular line is
y - 1 = -3(x + 2)
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