Math, asked by matthewmorgan92, 9 months ago

What is the equation of the line that passes through (−2,1) and is perpendicular to 3y=x-4

Answers

Answered by sakshisingh27
0

Step-by-step explanation:

Perpendicular lines have opposite-reciprocal slopes, so the slope of the line we want to find is 1/2. Plugging in the point given into the equation y = 1/2x + b and solving for b, we get b = 6. Thus, the equation of the line is y = ½x + 6. Rearranged, it is –x/2 + y = 6.

Answered by manobsaikia7
0

Answer:

The product of slopes of perpendicular lines is -1. The slope of the given line is

m1 = 1/3

The slope of the perpendicular line is

m2 = -1/m1 = -1/(1/3) = -3

In point slope form, the equation of the perpendicular line is

y - 1 = -3(x + 2)

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