What is the equation of the line that passes through (−2,1) and is perpendicular to the line that passes through the following points: (1,4),(−2,3)?
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Answer:
Step-by-step explanation:
For perpendicular lines the product of their slopes is -1.
This is m1*m2=-1.
M =y2-y1/x2-x1
m1=3-4/-2-1=-1/-3=1/3
M1=1/3.
For perpendicular lines m1*m2=-1
hence, 1/3*m2=-1
m2=-3
to find the equation of the perpendicular line; (-2, 1),(x, y)
y-1/x--2=-3
y-1=-3(x+2)=-3x-6
y=-3x-6+1=-3x-5
hence, y=-3x-5
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