Question

What is the equation of the line that passes through (3, –1) and is perpendicular to the line y = -3x +2 ?

Question 8 options:

A. y= -(1/3)x +2


B. y = (1/3)x +2


C. y= (1/3)x -2


D. None of the above

Answer 1

Step-by-step explanation:

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$8451873091$

Answer 2

Answer:

The line is passing through the given point (3,−1,2) and is perpendicular to the

b

1

and

b

2

.

Where

b

1

=2

i

−2

j

+

k

And

b

2

=

i

−2

j

+2

k

Let line perpendicular to

b

1

and

b

2

is

c

.

c

=

b

1

×

b

2

=

⎣

⎢

⎢

⎡

i

2

1

j

−2

−2

k

1

2

⎦

⎥

⎥

⎤

c

=

i

(−4+2)−

j

(4−1)+

k

(−4+2)

c

=

i

(−4+2)−

j

(4−1)+

k

(−4+2)

c

=−2

i

−3

j

−2

k

Direction ratios of

c

are a=−2,b=−3,c=−2

Thus, the equation of line passing through points (3,−2,1) having direction ratios a=−2,b=−3,c=−2 will be,

a

x−x

1

=

b

y−y

1

=

c

z−z

1

−2

x−3

=

−3

y+1

=

−2

z−2

Cancel negative sign from above equation

2

x−3

=

3

y+1

=

2

z−2

−

10

x

−

29

=

0