What is the equation of the line that passes through (3, –1) and is perpendicular to the line y = -3x +2 ?
Question 8 options:
A. y= -(1/3)x +2
B. y = (1/3)x +2
C. y= (1/3)x -2
D. None of the above
Answers
Answered by
0
Step-by-step explanation:
Answered by
0
Answer:
The line is passing through the given point (3,−1,2) and is perpendicular to the
b
1
and
b
2
.
Where
b
1
=2
i
−2
j
+
k
And
b
2
=
i
−2
j
+2
k
Let line perpendicular to
b
1
and
b
2
is
c
.
c
=
b
1
×
b
2
=
⎣
⎢
⎢
⎡
i
2
1
j
−2
−2
k
1
2
⎦
⎥
⎥
⎤
c
=
i
(−4+2)−
j
(4−1)+
k
(−4+2)
c
=
i
(−4+2)−
j
(4−1)+
k
(−4+2)
c
=−2
i
−3
j
−2
k
Direction ratios of
c
are a=−2,b=−3,c=−2
Thus, the equation of line passing through points (3,−2,1) having direction ratios a=−2,b=−3,c=−2 will be,
a
x−x
1
=
b
y−y
1
=
c
z−z
1
−2
x−3
=
−3
y+1
=
−2
z−2
Cancel negative sign from above equation
2
x−3
=
3
y+1
=
2
z−2
−
10
x
−
29
=
0
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