Question

What is the equation of the line that passes through (4, -1) and (-2, 3)? 2x - 3y - 5 = 0 2x + 3y - 5 = 0 -2x + 3y - 5 = 0

Answer 1

Answer: 2x + 3y - 5 = 0

Step-by-step explanation:

Let's find slope with given points first

(4,-1) & (-2,3)

slope (m) = (y2 - y1)/(x2 - x1)

m = 3 - (-1)/-2-4

m = -2/3

Line with slope, m = -2/3 and point (4,,-1) is

y - y1 = m(x-x1)

y - (-1) = -2/3(x-4)

3y + 3 = -2x + 8

2x + 3y - 5 = 0

Hope it will help u!

Thanks!