Question

What is the equation of the line that passes through the point (6,11) and is parallel to the line with the following equation?
y = 2/3x - 5


A. y = 2/3x +7

B. y = -3/2x - 17

C. y = 2/3x - 15

D. y = -3/2x + 5

Answer 1

Answer:

A

Step-by-step explanation:

The line equation is y=mx+c

if we place the points (6,11) in the (x,y) positions we can get the equation :

11=m(6)+c

now we need to find 'm'

when there are parallel lines to find gradient we know that they will be same

and so the gradient will remain:

2/3

place this in the first equation we formed to get 'c':

11= (2/3)(6) + c

11=4 + c

c= 7

and so

y=2/3x + 7

Answer 2

Answer: B.

Step-by-step explanation: