What is the equation of the line that passes through the point (6,11) and is parallel to the line with the following equation?
y = 2/3x - 5
A. y = 2/3x +7
B. y = -3/2x - 17
C. y = 2/3x - 15
D. y = -3/2x + 5
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Answer:
A
Step-by-step explanation:
let the equation of required line be y= mx + c , where m is slope of line and c is y-intercept.
parallel lines have same slope,
slope of given line = 2/3
therefore m = 2/3
equation of required line becomes y = (2/3)x + c
since this line passes through point (6, 11) , (6 11) should satisfy the equation.
=> 11 = (2/3)*6 + c
=> 11 = 4 + c
=> c = 7
hence equation of required line is
y = (2/3)x + 7
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