Question

What is the equation of the line that passes through the point (-2,14) and is perpendicular to the line with the following equation?
y = - 2/5x -1

a. y = -5/2x + 9

b. y = -2/5x + 16

c. y = -2/5x + 12

d. y = 5/2x + 19

Answer 1

Answer:

What is the equation of the line that passes through the point (-2,14) and is perpendicular to the line with the following equation?

y = - 2/5x -1

a. y = -5/2x + 9

b. y = -2/5x + 16

c. y = -2/5x + 12

d. y = 5/2x + 19.

c.y = -2/5x + 12

Answer 2

Answer:

(d). y = (5/2)x + 19

Step-by-step explanation:

Slope of perpendicular lines are opposite reciprocals.

The given equation is y = (-2/5) x - 1 and slope of this equation is (-2/5)

Slope of perpendicular line to the given line is (5/2)

There is only one option (d). where is slope (5/2)

Thus, the answer is (d). y = (5/2)x + 19

Let plug in the coordinates of given points, just to check that we choose the correct answer:

14 = (5/2) * (- 2) + 19

14 = 14

Done!!! :)