Question

What is the equation of the line that passes through the points (1, 3) and (4, 6)?

Answer 1

Answer:

❤️❤️❤️

$\bold{y=x+2,}$

Explanation:

The equation of a line in  slope-intercept form  is:

• $\bold{y=mx+b}$

where m is the slope and b the y - intercept

to calculate m use the gradient formula:

• $\bold{m=\frac{y_2-y_1}{x_2-x_1}, }$

Let $\bold{(x_1,y_1)}=(1,3) \:and\: \bold{(x_2,y_2)}=(4,6)$

$\bold{m=\frac{6-3}{4-1}=\frac{3}{3}=1, }$

$\bold{y=x+b}$ is the partial equation

to find b substitute either of the 2 given points into the partial equation

using (1,3) then,

3= l + b=b=3-1=2,

y=x+2 is the  equation of the line.