Question

What is the equation of the line that passes through the point (-3,0) and has a slope of 4/3 ?

Answer 1

Answer:

Given, slope=−4/3

The line passes through the point (−3,4)=(x

1

,y

1

)

Now, on substituting the values in y−y

1

=m(x−x

1

), we have

y−4=−4/3(x+3)

3y−12=−4x−12

4x+3y=0

Hence, the above is the required line equation.

Answer 2

Step-by-step explanation:

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