what is the equation of the line that passes through the point (-2,-6) and has a slope of -1/2
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Answered by
1
Answer:
x + 2y+14 =0
Step-by-step explanation:
Equation of a line having slope m and passing through ( a,b) is y - a = m (x - b)
Therefore the required Equation is
y - (-6) = (-1/2) ( x - (-2))
y + 6 = (-1/2)(x + 2)
2y + 12 = -x-2
x + 2y+ 14=0
Answered by
0
y=mx + c
m=-1\2
y=-1\2x + c
c is y intercept
-6=(-1\2×-2)+c
-6=-1+c
-6+1=c
-5=c
y=-1\2x-c
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