What is the equation of the line that passes through the point (3,2) and has a slope of 2/3?
Answers
Answer: y = 2x/3
Step-by-step explanation:
The formula to find the equation of a line(one of the formulas) is slope-intercept form.
This is: y = mx + b
M is the slope
B is the y intercept
Y is the value of the y coordinate
X is the value of the x coordinate
We know the slope
So,
We can substitute m for 2/3
Thus, y = (2/3)*x + b, so y = 2x/3 + b
Also, since we know one of the coordinates of the line, we can substitute 3 for x and 2 for y.
So, 2 = (2*3)/3 + b
Now we solve for b,
2= 6/3 + b
2 = 2+b
B= 0
By the addition property of 0, adding 0 to a number results in itself, so really, the equation is:
Y= 2x/3
Answer :
You are given a point and a slope ( m )
The equation of a line in point slope from is :
y - y 1 = m ( x - x1 )
x1 and y1 come from the point given ( 3,2 ) and m is the slope which is 2/3
Now plug in your numbers to the equation .
y - 2 = 2/3. ( x - 3 ) this is the equation of a line in point slope form .
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